乌拉圭VS俄罗斯滚球

抽样打印连接编号(比如尾号是1)的调试日志。通过前面介绍可以知道,maxThreads数量应该远大于CPU核心数量;而且CPU核心数越大,maxThreads应该越大;应用中CPU越不密集(IO越密集),maxThreads应该越大,以便能够充分利用CPU。其中,ps-eLopid,stat|grep27989输出的结果如下:图中只截图了部分结果;Sl表示大多数线程都处于空闲状态。学习任何东西都是有用的,因为你尝试的编程技术和工具越多,再用其他的工具就会越容易。??????????Stringfoundstring="";??????????if(found){????????????foundstring=m.group();????????????Stringfoundstring0=m.group(0);?//group(),group(0)返回符合整个表达式的子字符串????????????Stringfoundstring1=m.group(1);?//group(1)返回符合整个表达式的子字符串中匹配第一个表达式的子字符串????????????Stringfoundstring2=m.group(2);?//group(2)返回符合整个表达式的子字符串中匹配第一个表达式的子字符串//?????????Stringfoundstring3=m.group(3);????????????System.out.println("foundstring:"+foundstring);???????????System.out.println("foundstring0:"+foundstring0);???????????System.out.println("foundstring1:"+foundstring1);???????????System.out.println("foundstring2:"+foundstring2);//?????????System.out.println("foundstring3:"+foundstring3);??????????}??????????returnfoundstring;?????}??????/**?????*返回给定字符串中匹配给定正则表达式所有子字符串?????*@paramregex?????*@paramdecStr?????*@returnList:返回所有匹配正则表达式的子字符串?????*/?????publicstaticListsearchSubStr(Stringregex,StringdecStr){??????????Patternp=Pattern.compile(regex,Pattern.CASE_INSENSITIVE);??????????Matcherm=p.matcher(decStr);???????????Listlist=newArrayList();??????????while(m.find()){??//12a345b666cwer??????????????list.add(m.group());??????????}??????????for(Stringstring:list){??????????????System.out.println(string);??????????}??????????returnlist;?????}??????/**?????*替换给定字符串中匹配正则表达式的子字符串?????*@paramregex:正则表达式?????*@paramdecStr:所要匹配的字符串?????*@paramreplaceStr:将符合正则表达式的子串替换为该字符串?????*@return:返回替换以后新的字符串?????*/?????publicstaticStringreplace(Stringregex,StringdecStr,StringreplaceStr){??????????Patternp=Pattern.compile(regex,Pattern.CASE_INSENSITIVE);??????????Matcherm=p.matcher(decStr);??????????//替换??????????Stringnewstring=m.replaceAll(replaceStr);??????????System.out.println(newstring);??????????returnnewstring;?????}??????publicstaticvoidtestSplit(){??????????Stringstr="abc5Adefghi7Ajklmn";??????????//分割??????????String[]strs=str.split("(\d)A");??????????for(inti=0;i??????????????System.out.println(strs[i]);??????????}?????}?????????publicstaticvoidmain(String[]args){??????????replace("\d","dsfd;sa;ksd12a34b567c890d888e999f","*");//???????System.out.println(validate("\d+","334455aaa"));//???????System.out.println(validate2("\d+","334455aaa"));//???????System.out.println(searchSubStr("(\d+)([a-z]+)","334455aaa--3232423aaa-32324bbb"));??????????testSplit();?????}}高并发性能调试经验分享{###}(点击上方公众号,可快速关注)来源:罗成?@互联网罗成?:http://weibo.com/u/1822556675链接:https://zhuanlan.zhihu.com/p/21348220引文4月份的时候看到一道面试题,据说是腾讯校招面试官提的:在多线程和高并发环境下,如果有一个平均运行一百万次才出现一次的bug,你如何调试这个bug?知乎原贴地址如下:腾讯实习生面试,这两道题目该怎么回答??编程?.(https://www.zhihu.com/question/43416744)遗憾的是知乎很多答案在抨击这道题本身的正确性,虽然我不是这次的面试官,但我认为这是一道非常好的面试题。